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David and Michael charged Mr. Jimenez $3,000 toremodel his basement.?

David and Michael charged Mr. Jimenez $3,000 to remodel his basement. To complete the project, David worked 4 days alone, Michael worked 1 day alone, and they worked 10 days together. If they each received the same amount of money for each day that they worked, how much of the $3,000 did David receive? (A) $1,800 (B) $1,750 (C) $1,680 (D) $1,575 (E) $1,200

Public Comments

  1. Compute man-days for each person. Then divide the $3K by the number of man days. Multiply this result by 14, the number of man-days David worked.
  2. the ratio of david's working days to michael's 4 : 1 total they work 5 days to get 10 days 8 : 2 $3000 / 10 days = $300 since David worked 8 days, he should get $300 times 8 days = $2400
  3. let rate per day be x for both 4x+x+10*2x=3000 25x=3000 x=120 Since David worked for 14 days in all Therefore, David received =14*120 =1680 Ans. (c)
  4. c DEFINITELY ADD ALL DAYS IN TOTAL 10 PLUS 10 PLUS 1 PLUS 4 EQUALS 25 THEN DIVIDE INTO 3000 AND FIND DAILY PAY AND THEN TIMES EACH PERSONS AMOUNT OF DAY BY THE PAY KIM